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(G)=3G^2-5G+5
We move all terms to the left:
(G)-(3G^2-5G+5)=0
We get rid of parentheses
-3G^2+G+5G-5=0
We add all the numbers together, and all the variables
-3G^2+6G-5=0
a = -3; b = 6; c = -5;
Δ = b2-4ac
Δ = 62-4·(-3)·(-5)
Δ = -24
Delta is less than zero, so there is no solution for the equation
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